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08-22-2007, 10:54 AM
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Simplifying Radical Expressions
Why does a^1/4 x b^2/4 = (ab^2)^1/4?
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Excelsior, BS Finance, pursuing degree Studying: DSST P. of Stat. Completed: CLEP: Hum. (67), Hist. of U.S. I (74), Hist. of U.S. II (71), Intro. Psych. (69), Intro. Soc. (72), Soc. Sci. and Hist. (74), Western Civ I (72), Western Civ II (70), Am. Lit. (60), Intro. to Educ. Psych. (62), P. of Management (74), P. of Market. (74), Intro. Bus. Law (67), P. of Accounting (60), AmGov (68) DSST: Ethics in Am. (76), P. of Super.(67), HRM (65), Intro to Bus. (70), MIS (65), P. of Fin (62), M&B (65) ECE: OB (B) Total Credits: 105     
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08-23-2007, 11:40 AM
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Hopefully you can understand this from the notation. I think if you write it down the solution will make more sense. It may help to clarify it if you write the equation reversed
(i.e. (ab^2)^1/4=a^1/4*b^2/4) a^1/4*b^2/4=(ab^2)^1/4 (remember ONLY the "b" term is squared) is the same as: a^1/4*b^2/4=(a^1b^2)^1/4 So you could say: a^1/4*b^2/4=(a^1)^1/4*(b^2)^1/4 which is the same as saying: a^((1*1)/4)*b^((2*1)/4) Hope this helps!
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Linear Mode
